Chemistry exam scores. Structure of CMMs in chemistry

20.10.2021 Diseases

Federal Service for Supervision in Education and Science
(Rosobrnadzor)
02/27/2019

No. 10-151 federal Service for supervision in the field of education and science in accordance with paragraph 21 of the Procedure for conducting state final certification for educational programs of basic general education, approved by order of the Ministry of Education of Russia and Rosobrnadzor dated November 7, 2018 No. 189/1513 (registered by the Ministry of Justice of Russia on December 10, 2018, registration No. 52953) (hereinafter referred to as the Procedure), sends for use in the work recommendations for determining the minimum quantity primary points , confirming that students have completed educational programs of basic general education in accordance with the requirements of the federal state educational standard basic general education (hereinafter - minimal amount primary points), recommendations for converting the amount of primary points for examination papers of the main state exam (hereinafter - OGE) and the state final exam (hereinafter - GVE).

into a five-point assessment system in 2019 In accordance with paragraph 22 of the Procedure, executive authorities of the subjects Russian Federation

, carrying out public administration in the field of education, ensure the conduct of state final certification for educational programs of basic general education, including determining the minimum number of primary points, and also ensure the transfer of the sum of primary points for examination papers of the OGE and GVE into a five-point assessment system. Application: for 14 l.

Deputy Head: A.A. Muzaev Scale for recalculating the primary score for completion exam paper

to a mark on a five-point scale.

2019 Chemistry.

year.

    The maximum number of points that an OGE participant can receive for completing the entire examination work (without a real experiment) is 34 points.

    0-8 points - mark “2”

    9-17 points - mark “3”

    18-26 points - mark “4”

The exam results can be used when admitting students to specialized classes for training in educational programs of secondary general education.

The guideline for selection into specialized classes can be an indicator whose lower limit corresponds to 23 points.

    The maximum number of points that an OGE participant can receive for completing the entire examination work (without a real experiment) is 34 points.

    The maximum number of points that a participant in the OGE can receive for completing the entire examination work (with a real experiment) is 38 points.

    9-18 points - mark “3”

    19-28 points - mark “4”

29-38 points - mark “5”

The exam results can be used when admitting students to specialized classes for training in educational programs of secondary general education. A guideline for selection into specialized classes can be an indicator whose lower limit corresponds to 25 points.

2018

    Scale for converting the primary score for completing an examination paper into a mark on a five-point scale (work without a real experiment, demo version 1)

    0-8 points - mark “2”

    9-17 points - mark “3”

    18-26 points - mark “4”

27-34 points - mark “5”

The exam results can be used when admitting students to specialized classes in secondary schools.

    Scale for converting the primary score for completing an examination paper into a mark on a five-point scale (work without a real experiment, demo version 1)

    The guideline for selection into specialized classes can be an indicator whose lower limit corresponds to 23 points.

    Scale for converting the primary score for completing an examination paper into a mark on a five-point scale (working with a real experiment, demo version 2)

    9-18 points - mark “3”

19-28 points - mark “4”

29-38 points - mark “5”

2018

    Scale for converting the primary score for completing an examination paper into a mark on a five-point scale (work without a real experiment, demo version 1)

    0-8 points - mark “2”

    9-17 points - mark “3”

    18-26 points - mark “4”

2017

The exam results can be used when admitting students to specialized classes in secondary schools.

    Scale for converting the primary score for completing an examination paper into a mark on a five-point scale (work without a real experiment, demo version 1)

    The guideline for selection into specialized classes can be an indicator whose lower limit corresponds to 23 points.

    Scale for converting the primary score for completing an examination paper into a mark on a five-point scale (working with a real experiment, demo version 2)

    9-18 points - mark “3”

The maximum number of points that an examinee can receive for completing the entire examination paper (without the actual experiment) is 34 points.

The maximum number of points that an examinee can receive for completing the entire examination paper (with a real experiment) is 38 points.

29-38 points - mark “5”

2018

    Scale for converting the primary score for completing an examination paper into a mark on a five-point scale (work without a real experiment, demo version 1)

    0-8 points - mark “2”

    9-17 points - mark “3”

    18-26 points - mark “4”

27-34 points - mark “5”

2017

The exam results can be used when admitting students to specialized classes in secondary schools.

    Scale for converting the primary score for completing an examination paper into a mark on a five-point scale (work without a real experiment, demo version 1)

    The guideline for selection into specialized classes can be an indicator whose lower limit corresponds to 23 points.

    Scale for converting the primary score for completing an examination paper into a mark on a five-point scale (working with a real experiment, demo version 2)

    9-18 points - mark “3”

The maximum number of points that an examinee can receive for completing the entire examination paper (without the actual experiment) is 34 points.

The exam results can be used when admitting students to specialized classes in secondary schools. A guideline for selection into specialized classes can be an indicator whose lower limit corresponds to 25 points.

29-38 points - mark “5”

2018

    Scale for converting the primary score for completing an examination paper into a mark on a five-point scale (work without a real experiment, demo version 1)

    0-8 points - mark “2”

    9-17 points - mark “3”

    18-26 points - mark “4”

2016

2017

The exam results can be used when admitting students to specialized classes in secondary schools.

    Scale for converting the primary score for completing an examination paper into a mark on a five-point scale (work without a real experiment, demo version 1)

    The guideline for selection into specialized classes can be an indicator whose lower limit corresponds to 23 points.

    Scale for converting the primary score for completing an examination paper into a mark on a five-point scale (working with a real experiment, demo version 2)

    9-18 points - mark “3”

The maximum number of points that an examinee can receive for completing the entire examination paper (without the actual experiment) is 34 points.

2015

29-38 points - mark “5”

2018

    Scale for converting the primary score for completing an examination paper into a mark on a five-point scale (work without a real experiment, demo version 1)

    0-8 points - mark “2”

    9-17 points - mark “3”

    18-26 points - mark “4”

2016

2017

The exam results can be used when admitting students to specialized classes in secondary schools.

    Scale for converting the primary score for completing an examination paper into a mark on a five-point scale (work without a real experiment, demo version 1)

    The guideline for selection into specialized classes can be an indicator whose lower limit corresponds to 23 points.

    Scale for converting the primary score for completing an examination paper into a mark on a five-point scale (working with a real experiment, demo version 2)

    9-18 points - mark “3”

The maximum number of points that an examinee can receive for completing the entire examination paper (without the actual experiment) is 34 points.

It is recommended to mark “5” if, out of the total score sufficient to obtain this mark, the graduate scored 5 or more points for completing the tasks of Part 3. The exam results can be used when admitting students to specialized classes of secondary school.

    Scale for converting the primary score for completing an examination paper into a mark on a five-point scale (work without a real experiment, demo version 1)

    0-8 points - mark “2”

    9-17 points - mark “3”

    27-33 points - mark “5”

It is recommended to give the mark “5” if, out of the total amount of points sufficient to obtain this mark, the graduate scored 5 or more points for completing the tasks of part 3.

year 2012.

The maximum number of points that an examinee can receive for completing the entire examination work is 33 points.

    Scale for converting the primary score for completing an examination paper into a mark on a five-point scale (work without a real experiment, demo version 1)

    0-8 points - mark “2”

    9-17 points - mark “3”

    27-33 points - mark “5”

It is recommended to give the mark “5” if, out of the total amount of points sufficient to obtain this mark, the graduate scored 5 or more points for completing the tasks of part 3.
The exam results can be used when admitting students to specialized classes in secondary schools. The guideline for selection into specialized classes can be an indicator whose lower limit corresponds to 23 points.

2011.

    Scale for converting the primary score for completing an examination paper into a mark on a five-point scale (work without a real experiment, demo version 1)

    0-8 points - mark “2”

    9-17 points - mark “3”

    27-33 points - mark “5”

The proposed lower limit of points for marking “3” is a guideline for territorial subject commissions and can be reduced, but not lower than to 6 points.

The exam results can be used when admitting students to specialized classes in secondary schools. The guideline for selection into specialized classes can be an indicator whose lower limit corresponds to 23 points.

2010

    0-10 points - mark “2”

    11-19 points - mark “3”

    20-28 points - mark “4”

    29-34 points - mark “5”

year 2009.

    0-10 points - mark “2”

    11-18 points - mark “3”

    19-27 points - mark “4”

    28-33 points - mark “5”

Municipal budgetary educational institution

“Secondary school No. 4, Shebekino, Belgorod region”

Features of solving and evaluating tasks 30-35 of the Unified State Exam in chemistry

Prepared by: Arnautova Natalya Zakharovna,

teacher of chemistry and biology

MBOU "Secondary school No. 4, Shebekino, Belgorod region"

2017

Methodology for assessing tasks with a detailed answer (main approaches to determining criteria and rating scales for completing tasks)

The basis of the methodology for assessing tasks with a detailed answer is a number of general provisions. The most important among them are the following:

Testing and evaluation of tasks with a detailed answer is carried out only through an independent examination based on the method of element-by-element analysis of the examinees' answers.

The use of the element-by-element analysis method makes it necessary to ensure that the wording of the task conditions clearly corresponds to the content elements being checked. The list of content elements tested by any assignment is consistent with the standard requirements for the level of preparation of high school graduates.

The criterion for assessing the completion of a task using the method of element-by-element analysis is to establish the presence in the answers of the examinees of the answer elements given
in the response model. However, another answer model proposed by the examinee may be accepted if it does not distort the essence of the chemical component of the task conditions.

The rating scale for task performance is established depending on the number of content elements included in the response model, and taking into account factors such as:

Level of complexity of the content being tested;

A specific sequence of actions that should be carried out when performing a task;

Unambiguous interpretation of the task conditions and possible options for wording the answer;

Compliance of the assignment conditions with the proposed assessment criteria for individual content elements;

Approximately the same level of difficulty for each of the content elements tested by the task.

When developing assessment criteria, the features of the content elements of all five long-answer tasks included in the examination paper are taken into account. It is also taken into account that the records of the examinees’ answers can be either very general, streamlined and not specific, or too brief
and insufficiently reasoned. Close attention is paid to highlighting the elements of the answer that are worth one point. This takes into account the inevitability of a gradual increase in the difficulty of obtaining each subsequent point
for a correctly formulated element of content.

When drawing up a scale for grading calculation problems (33 and 34), the possibility of different ways of solving them is taken into account, and therefore, the presence in the examinee’s answer of the main stages and results of completing the tasks indicated
in the evaluation criteria. Let us illustrate the methodology for assessing tasks with a detailed answer using specific examples.

2017-2018 academic year

Tasks

Maximum score

Job Level

Task 30

2016-2017

Tasks 30 are aimed at testing the ability to determine the degree of oxidation chemical elements, determine the oxidizing agent and the reducing agent, predict the products of redox reactions, establish the formulas of substances missed in the reaction scheme, draw up an electronic balance, and on its basis assign coefficients in reaction equations.

The scale for assessing the performance of such tasks includes the following elements:

 an electronic balance has been compiled – 1 point;

 the oxidizing agent and the reducing agent are indicated – 1 point.

 formulas of missing substances are determined and coefficients are assigned
in the equation of redox reaction – 1 point.

Example task:

Using the electron balance method, create an equation for the reaction

Na 2 SO 3 + … + KOH K 2 MnO 4 + … + H 2 O

Identify the oxidizing agent and the reducing agent.

Points

Possible answer

Mn +7 + ē → Mn +6

S +4 – 2ē → S +6

Sulfur in the +4 oxidation state (or sodium sulfite due to sulfur in the +4 oxidation state) is a reducing agent.

Manganese in oxidation state +7 (or potassium permanganate due to manganese
in the oxidation state +7) – oxidizing agent.

Na 2 SO 3 + 2KMnO 4 + 2KOH = Na 2 SO 4 + 2K 2 MnO 4 + H 2 O

The answer is correct and complete:

    the degree of oxidation of elements that are, respectively, an oxidizing agent and a reducing agent in the reaction is determined;

    oxidation and reduction processes were recorded, and an electronic (electron-ion) balance was compiled on their basis;

    the missing substances in the reaction equation are determined, all the coefficients are placed

Maximum score

When assessing the examinee’s answer, it is necessary to take into account that there are no uniform requirements for the formatting of the answer to this task. As a result, the compilation of both electronic and electron-ion balances is accepted as the correct answer, and the indication of the oxidizing agent and reducing agent can be done in any clearly understandable way. However, if the answer contains elements of the answer that are mutually exclusive in meaning, then they cannot be considered correct.

2018 format tasks

1. Task 30 (2 points)

To complete the task, use following list substances: potassium permanganate, hydrogen chloride, sodium chloride, sodium carbonate, potassium chloride. It is permissible to use aqueous solutions of substances.

From the proposed list of substances, select substances between which an oxidation-reduction reaction is possible, and write down the equation for this reaction. Make an electronic balance, indicate the oxidizing agent and reducing agent.

Explanation.

Let's write the reaction equation:

Let's create an electronic balance:

Chlorine in oxidation state −1 is a reducing agent. Manganese in the oxidation state +7 is an oxidizing agent.TOTAL 2 points

    substances are selected, the equation of the redox reaction is written, and all the coefficients are set.

    oxidation and reduction processes were recorded, and an electronic (electron-ion) balance was compiled on their basis; which are respectively the oxidizing agent and the reducing agent in the reaction;

There was an error in only one of the response elements listed above

There were errors in two of the above response elements

All elements of the answer are written incorrectly

Maximum score

2018 format tasks

1. Task 31 (2 points)

To complete the task, use the following list of substances: potassium permanganate, potassium bicarbonate, sodium sulfite, barium sulfate, potassium hydroxide. It is permissible to use aqueous solutions of substances.

Explanation.

Possible answer:

2. Task 31

To complete the task, use the following list of substances: hydrogen chloride, silver(I) nitrate, potassium permanganate, water, nitric acid. It is permissible to use aqueous solutions of substances.

From the proposed list of substances, select substances between which an ion exchange reaction is possible. Write down the molecular, complete and abbreviated ionic equations for this reaction.

Explanation.

Possible answer:

Task 32. 2018 format tasks

In the condition of task 32, testing knowledge of the genetic relationship of various classes of inorganic substances, a description of a specific chemical experiment is proposed, the progress of which the examinees will have to illustrate using the equations of the corresponding chemical reactions. The grading scale for the task remains the same as in 2016, equal to 4 points: each correctly written reaction equation is scored 1 point.

Example task:

Iron was dissolved in hot concentrated sulfuric acid. The resulting salt was treated with an excess of sodium hydroxide solution. The brown precipitate that formed was filtered and calcined. The resulting substance was heated with iron.

Write equations for the four reactions described.

Contents of the correct answer and assessment instructions(other wording of the answer is allowed that does not distort its meaning)

Points

Possible answer

Four equations for the described reactions are written:

1) 2Fe + 6H 2 SO 4
Fe 2 (SO 4 ) 3 + 3SO 2 + 6H 2 O

2) Fe 2 (SO 4 ) 3 + 6NaOH = 2Fe(OH) 3 + 3Na 2 SO 4

3) 2Fe(OH) 3
Fe 2 O 3 + 3H 2 O

4) Fe 2 O 3 + Fe = 3FeO

All reaction equations are written incorrectly

Maximum score

It should be noted that the absence of coefficients (at least one) before the formulas of substances in reaction equations is considered an error. No points are awarded for such an equation.

Task 33. 2018 format tasks

Tasks 33 test the assimilation of knowledge about the relationship of organic substances and provide for checking five elements of content: the correctness of writing five reaction equations corresponding to the diagram - a “chain” of transformations. When writing reaction equations, examinees must use the structural formulas of organic substances. The presence of each checked content element in the answer is scored 1 point. The maximum number of points for completing such tasks is 5.

Example task:

Write the reaction equations that can be used to carry out the following transformations:

When writing reaction equations, use the structural formulas of organic substances.

Contents of the correct answer and assessment instructions
Other wording of the answer is allowed that does not distort its meaning)

Points

Possible answer

Five reaction equations have been written corresponding to the transformation scheme:

Five reaction equations written correctly

Four reaction equations written correctly

Three reaction equations written correctly

Two reaction equations written correctly

One reaction equation written correctly

All elements of the answer are written incorrectly

Maximum score

Note that in the examinee’s answer it is permissible to use structural formulas different types(expanded, contracted, skeletal), unambiguously reflecting the bond order of atoms and the relative arrangement of substituents and functional groups
in a molecule of organic matter.

Task 34. 2018 format tasks

Tasks 34 are calculation problems. Their implementation requires knowledge chemical properties substances and involves the implementation of a certain set of actions to ensure that the correct answer is obtained. Among such actions we name the following:

– drawing up equations of chemical reactions (according to the data of the problem conditions) necessary to perform stoichiometric calculations;

– performing calculations necessary to find answers to questions
in the problem statement there are questions;

– formulating a logically substantiated answer to all questions posed in the task conditions (for example, establishing a molecular formula).

However, it should be borne in mind that not all of the named actions must necessarily be present when solving any calculation problem, and in some cases some of them can be used more than once.

The maximum score for completing the task is 4 points. When checking, you should first of all pay attention to the logical validity of the actions performed, since some tasks can be solved in several ways. At the same time, in order to objectively evaluate the proposed method for solving the problem, it is necessary to check the correctness of the intermediate results that were used to obtain the answer.

Example task:

Determine the mass fractions (in%) of iron(II) sulfate and aluminum sulfide
in a mixture if, when 25 g of this mixture is treated with water, a gas is released that completely reacts with 960 g of a 5% solution of copper sulfate.

In your answer, write down the reaction equations that are indicated in the problem statement,
and provide all the necessary calculations (indicate the units of measurement of the required physical quantities).

Points

Possible answer

The reaction equations were compiled:

The amount of hydrogen sulfide is calculated:

The amount of substance and mass of aluminum sulfide and iron(II) sulfate are calculated:

The mass fractions of iron(II) sulfate and aluminum sulfide in the initial mixture were determined:

ω(FeSO 4 ) = 10 / 25 = 0.4, or 40%

ω(Al 2 S 3 ) = 15 / 25 = 0.6, or 6 0%

The answer is correct and complete:

    the answer correctly contains the reaction equations corresponding to the conditions of the task;

    calculations have been carried out correctly using the necessary physical quantities specified in the task conditions;

    a logically substantiated relationship between the physical quantities on the basis of which calculations are carried out is demonstrated;

    in accordance with the task conditions, the required physical quantity is determined

There was an error in only one of the response elements listed above

All elements of the answer are written incorrectly

Maximum score

When checking the answer, the examinee must take into account the fact that if the answer contains an error in calculations in one of the three elements (second, third or fourth), which led to an incorrect answer, the mark for completing the task is reduced by only 1 point.

Task 35. 2018 format tasks

Tasks 35 involve determining the molecular formula of a substance. Completing this task includes the following sequential operations: carrying out the calculations necessary to establish the molecular formula of an organic substance, writing the molecular formula of an organic substance, drawing up a structural formula of a substance that uniquely reflects the order of bonds of atoms in its molecule, writing a reaction equation that meets the conditions of the task.

The grading scale for task 35 in part 2 of the examination paper will be 3 points.

Tasks 35 use a combination of tested content elements - calculations, on the basis of which they come to determine the molecular formula of a substance, compile a general formula of a substance, and then determine the molecular and structural formula of a substance on its basis.

All these actions can be performed in different sequences. In other words, the examinee can come to the answer in any logical way available to him. Therefore, when assessing a task, the main attention is paid to the correctness of the chosen method for determining the molecular formula of a substance.

Example task:

When a sample of some organic compound weighing 14.8 g is burned, 35.2 g of carbon dioxide and 18.0 g of water are obtained.

It is known that the relative vapor density of this substance with respect to hydrogen is 37. During the study of the chemical properties of this substance, it was established that when this substance interacts with copper(II) oxide, a ketone is formed.

Based on the data of the task conditions:

1) make the calculations necessary to establish the molecular formula of an organic substance (indicate the units of measurement of the required physical quantities);

write down the molecular formula of the original organic substance;

2) draw up a structural formula of this substance, which unambiguously reflects the order of bonds of atoms in its molecule;

3) write the equation for the reaction of this substance with copper(II) oxide using the structural formula of the substance.

Contents of the correct answer and assessment instructions

(other wording of the answer is allowed that does not distort its meaning)

Points

Possible answer

The amount of combustion product substance found:

General formula substances – C x H y O z

n(CO2) = 35.2 / 44 = 0.8 mol; n (C) = 0.8 mol

n(H 2 O) = 18.0 / 18 = 1.0 mol; n(H) = 1.0 ∙ 2 = 2.0 mol

m(O) = 14.8 – 0.8 ∙ 12 – 2 = 3.2 g; n(O) = 3.2 ⁄ 16 = 0.2 mol

The molecular formula of the substance was determined:

x:y:z = 0.8:2:0.2 = 4:10:1

The simplest formula is C 4 H 10 O

M simple (C 4 H 10 O) = 74 g/mol

M source (C x H y O z ) = 37 ∙ 2 = 74 g/mol

Molecular formula of the starting substance – C 4 H 10 O

The structural formula of the substance has been compiled:

The equation for the reaction of a substance with copper(II) oxide is written:

The answer is correct and complete:

    the calculations necessary to establish the molecular formula of a substance have been correctly performed; the molecular formula of the substance is written down;

    the structural formula of the organic substance is written down, which reflects the bond order and relative arrangement of substituents and functional groups in the molecule in accordance with the assignment conditions;

    the equation of the reaction, which is indicated in the task conditions, is written using the structural formula of an organic substance

There was an error in only one of the response elements listed above

There were errors in two of the above response elements

There were errors in three of the above response elements

All elements of the answer are written incorrectly

All elements of the answer are written incorrectly

Maximum score

TOTAL part 2

2+2+ 4+5+4 +3=20 points

Bibliography

1. Methodological materials for chairmen and members of subject commissions of the constituent entities of the Russian Federation on checking the completion of tasks with a detailed answer from exam questions Unified State Examination works 2017. Article “Methodological recommendations for assessing the performance of Unified State Examination tasks with a detailed question.” Moscow, 2017.

2. FIPI project of control and measuring materials for the Unified State Exam 2018.

3. Demo versions, specifications, codifiers of the Unified State Exam 2018. FIPI website.

4. Information about planned changes to the 2018 CMM. FIPI website.

5.Site “I will solve the Unified State Exam”: chemistry, for an expert.

One of the elective subjects that a high school graduate indicates in the application is the Unified State Exam in Chemistry 2018. Test materials in chemistry are prepared in accordance with the Federal Standard of Complete Secondary Education. They are completely aimed at the school level. The difficulty is that in secondary schools only one hour a week is allocated for the study of chemistry. Therefore, in order to successfully pass the Unified State Exam in Chemistry, you must prepare persistently and purposefully.

Who chooses chemistry for the Unified State Exam?

The Unified State Exam in Chemistry is chosen by 11th grade students who plan to further connect their lives with studying at higher educational institutions in this field of study.

  • As a rule, these are graduates seeking to enter technical universities that offer chemical specialties as a training profile.
  • These could also be guys who want to enter medical universities, which require good knowledge of chemistry.

Basic documents of the Unified State Exam

If we talk about the content of the exam test in chemistry, then here you need to get acquainted with three main documents:

1)Codifier, consisting of two parts.

  • The first part of the document presents those elements of content that all tasks included in the option are aimed at checking for completeness.
  • The second part of the codifier is called “List of requirements for the level of training of graduates.” Here is a list of skills that an 11th grade student must master in order to complete the assignments.

2) Specification. This is a document that regulates the structure of the current year’s Unified State Examination. It presents topics that may appear on the exam.

3) Demo version of the Unified State Exam in chemistry- this is one version of the Unified State Exam, with which you need to start preparing for state exam in chemistry.
How to prepare? What to read?

There are quite a large number of manuals that are auxiliary materials:

  1. The books recommended by the Ministry of Education are chemistry textbooks.
  2. Benefits marked “FIPI”.
  3. Books by the developers of the Unified State Exam KIMs themselves in chemistry.

How does the Unified State Exam work?

Total 34 tasks
1 part part 2
29 short answer questions 5 tasks with detailed answers

The time to complete the entire exam is 210 minutes (3 hours 30 minutes).
The maximum primary score is 60.

Part 1 presents tasks for basic and higher level difficulties.

Part 2 contains high-level tasks.

Structure and typology of tasks of the 1st part of KIM

Part 1 tasks come in two main forms:

  1. short answer tasks that involve establishing correspondence between the positions of two sets;
  2. selecting several answer options from the list provided.

For example, in the 1st task basic level a number of chemical elements can be given (5 elements in total). Next, questions are asked that the graduate must read carefully and give the appropriate answer. The fact that there are two cells in the answer field indicates that there should be two such answers. And only if you select all the answer options correctly, you can get the maximum score for this task.

The second example of tasks is tasks on correspondence between two sets (5th task). Thus, formulas of substances can be presented in the left column, and in the right column - the class (group) of substances to which this or that substance belongs. Since there are 3 substances in the left column, the student must establish 3 correspondences.

If we talk about tasks of another type, then we can see tasks that contain textual information to a greater extent, where some kind of mental conduct of a chemical experiment is assumed and the choice of formulas of substances that will allow you to correctly answer the task presented in the task conditions.

Multiple-choice tasks often seem quite simple to students and do not require writing down reaction equations or formulas of substances. Unfortunately, it is not. Only if the graduate actually prescribes a solution for each task and is thoughtful about this condition problem, then in this case there is a probability of arriving at the correct answer.

Features of the tasks of the second part

But the tasks from the second part of the test with a detailed answer suggest a higher level of difficulty. But this does not go beyond the topics presented in the codifier. The complication is due to the fact that if in tasks of a basic level the test is aimed at one element of content, then in tasks of a high level of complexity the mastery of several elements of content or several skills is assumed. For example, you need not only to classify a particular substance into a class or group of substances, but also to remember what properties this group of substances has; sometimes you have to remember the specific properties of the substances discussed in the task.

Five tasks with detailed answers are aimed at the main, most important sections of the chemistry course. The entire option can be divided into certain content blocks, many of which are enlarged topics of the school chemistry course. For example, “Structure of the atom”, “Periodic laws. Periodic table of chemical elements”, “Inorganic substances”, “Organic substances”, “Methods of knowledge in chemistry”, “Chemistry in life”, “Calculations using chemical formulas, reaction equations”.

What can you use during the exam?

The graduate must bring two items to the chemistry exam:

  1. non-programmable calculator;
  2. black gel pen.

The exam will give you:

  • periodic system of chemical elements by D. I. Mendeleev;
  • table of solubility of acids, salts and bases;
  • electrochemical voltage series of metals (metal activity series).

The Ministry of Education does not intend to make any changes to the Unified State Exam KIM in chemistry in 2017–2018 academic year.

The date for the Unified State Examination in chemistry will be known in January 2018.

ABOUT Unified State Exam results in chemistry in 2018 can be found at your school or on the official website of the Unified State Exam.

For more information about the features of the Unified State Exam in chemistry, watch the video:

Table 1

The maximum number of points that an examinee can receive for completing the entire OGE exam paper in chemistry (without a real experiment) is 34 points.

The exam results can be used when admitting students to specialized classes in secondary schools. The guideline for selection into specialized classes can be an indicator whose lower limit corresponds to 23 points.

Scale for converting the primary score for completing an examination paper into a mark on a five-point scale (working with a real experiment, demo version 2)

table 2

The guideline for selection into specialized classes can be an indicator whose lower limit corresponds to 25 points.

The maximum number of points that an examinee can receive for completing the entire examination paper (with a real experiment) is 38 points.

A system for assessing the completion of individual tasks and the OGE 2018 exam paper in chemistry as a whole.

Students' answers to tasks in Part 1 are checked by experts or using a computer. Correct completion of each of tasks 1–15 is scored 1 point. Correct completion of each of tasks 16–19 is assessed with a maximum of 2 points.

Tasks 16 and 17 are considered completed correctly if two answer options are correctly selected in each of them. For an incomplete answer - one of two answers is correctly named or three answers are named, of which two are correct - 1 point is given. The remaining answer options are considered unfaithful and are scored 0 points.

Tasks 18 and 19 are considered completed correctly if three correspondences are correctly established. An answer in which two out of three matches are established is considered partially correct; it is worth 1 point. The remaining options are considered an incorrect answer and are scored 0 points.

The tasks of Part 2 (20–23) are checked by a subject commission. When assessing each of the three tasks, the expert, based on comparing the graduate’s answer with the sample answer given in the assessment criteria, identifies elements in the student’s answer, each of which is worth 1 point. Maximum score for a correctly completed task: for tasks 20 and 21 - 3 points each; in model 1 for task 22 – 5 points; in model 2 for task 22 - 4 points, for task 23 - 5 points.

Tasks with a detailed answer can be completed by students in different ways. Therefore, the sample solutions given in the evaluation criteria should be considered only as one of the possible answer options. This applies, first of all, to methods for solving calculation problems.

To pass final exams at school. It will need to be taken for admission to universities in the following areas: chemistry and chemical technology, medicine, construction, biotechnology and others. In general, the exam is not very popular - only one student out of ten graduates chooses chemistry.

Check out general information about the exam and start preparing. The KIM version of the Unified State Exam 2019 has some differences from last year: 1) in part 2 a task of a high level of difficulty with a detailed answer was added, 2) for four questions the level of difficulty and the maximum primary score were revised (for the entire test the maximum score did not change), 3) for To ensure a clearer distribution of tasks into thematic blocks, the developers slightly changed their order in Part 1.

Unified State Examination

Last year, to pass the Unified State Examination in chemistry with at least a C grade, it was enough to score 37 primary points. They were given, for example, for correctly completing the first 15 tasks of the test.

It is not yet known exactly what will happen in 2019: we need to wait for the official order from Rosobrnadzor on the correspondence of the primary and test scores. Most likely it will appear in December. Considering that the maximum primary score for the entire test remains the same, most likely the minimum score will not change either. Let's focus on these tables for now:

Structure of the Unified State Exam test

In 2019, the test consists of two parts, including 35 tasks.

  • Part 1: 29 tasks (1–29) with a short answer (number or sequence of numbers);
  • Part 2: 6 tasks (30–36) with detailed answers, complete solutions to the tasks are written down on answer sheet 2.

Preparation for the Unified State Exam

  • Take the Unified State Exam tests online for free without registration or SMS. The tests presented are identical in complexity and structure to the actual exams conducted in the corresponding years.
  • Download demo versions of the Unified State Examination in Chemistry, which will allow you to better prepare for the exam and pass it easier. All proposed tests have been developed and approved for preparation for the Unified State Exam by the Federal Institute of Pedagogical Measurements (FIPI). In the same FIPI all official Unified State Exam options.
    The tasks that you will see most likely will not appear on the exam, but will be similar to the demo ones, on the same topic or simply with different numbers.
  • Familiarize yourself with the basic exam prep formulas to help refresh your memory before attempting the demos and test options.

General Unified State Examination figures

Year Minimum Unified State Examination score Average score Number of participants Failed, % Qty
100 points
Duration -
Exam length, min.
2009 33
2010 33 56,04 83 544 6,2 275 180
2011 32 57,75 77 806 8,6 331 160
2012 36 57,3 93 181 11 365 180
2013 36 67,8 93 802 7,3 3220 180
2014 36 55,3 180
2015 36 56,3 180
2016 36 180
2017 36 180
2018